5.2x^2+3x-1,8=0

Solution for 5.2x^2+3x-1,8=0 equation:

5.2x^2+3x-1.8=0

a = 5.2; b = 3; c = -1.8;
Δ = b2-4ac
Δ = 32-4·5.2·(-1.8)
Δ = 46.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{46.44}}{2*5.2}=\frac{-3-\sqrt{46.44}}{10.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{46.44}}{2*5.2}=\frac{-3+\sqrt{46.44}}{10.4}
$